Optimal. Leaf size=219 \[ \frac {5 \left (b^2-4 a c\right )^{9/4} \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt {b d+2 c x d}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right )\right |-1\right )}{84 c^4 d^{5/2} \sqrt {a+b x+c x^2}}-\frac {5 \left (b^2-4 a c\right ) \sqrt {a+b x+c x^2} \sqrt {b d+2 c d x}}{84 c^3 d^3}+\frac {5 \left (a+b x+c x^2\right )^{3/2} \sqrt {b d+2 c d x}}{42 c^2 d^3}-\frac {\left (a+b x+c x^2\right )^{5/2}}{3 c d (b d+2 c d x)^{3/2}} \]
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Rubi [A] time = 0.18, antiderivative size = 219, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {684, 685, 691, 689, 221} \[ -\frac {5 \left (b^2-4 a c\right ) \sqrt {a+b x+c x^2} \sqrt {b d+2 c d x}}{84 c^3 d^3}+\frac {5 \left (b^2-4 a c\right )^{9/4} \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt {b d+2 c x d}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right )\right |-1\right )}{84 c^4 d^{5/2} \sqrt {a+b x+c x^2}}+\frac {5 \left (a+b x+c x^2\right )^{3/2} \sqrt {b d+2 c d x}}{42 c^2 d^3}-\frac {\left (a+b x+c x^2\right )^{5/2}}{3 c d (b d+2 c d x)^{3/2}} \]
Antiderivative was successfully verified.
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Rule 221
Rule 684
Rule 685
Rule 689
Rule 691
Rubi steps
\begin {align*} \int \frac {\left (a+b x+c x^2\right )^{5/2}}{(b d+2 c d x)^{5/2}} \, dx &=-\frac {\left (a+b x+c x^2\right )^{5/2}}{3 c d (b d+2 c d x)^{3/2}}+\frac {5 \int \frac {\left (a+b x+c x^2\right )^{3/2}}{\sqrt {b d+2 c d x}} \, dx}{6 c d^2}\\ &=\frac {5 \sqrt {b d+2 c d x} \left (a+b x+c x^2\right )^{3/2}}{42 c^2 d^3}-\frac {\left (a+b x+c x^2\right )^{5/2}}{3 c d (b d+2 c d x)^{3/2}}-\frac {\left (5 \left (b^2-4 a c\right )\right ) \int \frac {\sqrt {a+b x+c x^2}}{\sqrt {b d+2 c d x}} \, dx}{28 c^2 d^2}\\ &=-\frac {5 \left (b^2-4 a c\right ) \sqrt {b d+2 c d x} \sqrt {a+b x+c x^2}}{84 c^3 d^3}+\frac {5 \sqrt {b d+2 c d x} \left (a+b x+c x^2\right )^{3/2}}{42 c^2 d^3}-\frac {\left (a+b x+c x^2\right )^{5/2}}{3 c d (b d+2 c d x)^{3/2}}+\frac {\left (5 \left (b^2-4 a c\right )^2\right ) \int \frac {1}{\sqrt {b d+2 c d x} \sqrt {a+b x+c x^2}} \, dx}{168 c^3 d^2}\\ &=-\frac {5 \left (b^2-4 a c\right ) \sqrt {b d+2 c d x} \sqrt {a+b x+c x^2}}{84 c^3 d^3}+\frac {5 \sqrt {b d+2 c d x} \left (a+b x+c x^2\right )^{3/2}}{42 c^2 d^3}-\frac {\left (a+b x+c x^2\right )^{5/2}}{3 c d (b d+2 c d x)^{3/2}}+\frac {\left (5 \left (b^2-4 a c\right )^2 \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \int \frac {1}{\sqrt {b d+2 c d x} \sqrt {-\frac {a c}{b^2-4 a c}-\frac {b c x}{b^2-4 a c}-\frac {c^2 x^2}{b^2-4 a c}}} \, dx}{168 c^3 d^2 \sqrt {a+b x+c x^2}}\\ &=-\frac {5 \left (b^2-4 a c\right ) \sqrt {b d+2 c d x} \sqrt {a+b x+c x^2}}{84 c^3 d^3}+\frac {5 \sqrt {b d+2 c d x} \left (a+b x+c x^2\right )^{3/2}}{42 c^2 d^3}-\frac {\left (a+b x+c x^2\right )^{5/2}}{3 c d (b d+2 c d x)^{3/2}}+\frac {\left (5 \left (b^2-4 a c\right )^2 \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-\frac {x^4}{\left (b^2-4 a c\right ) d^2}}} \, dx,x,\sqrt {b d+2 c d x}\right )}{84 c^4 d^3 \sqrt {a+b x+c x^2}}\\ &=-\frac {5 \left (b^2-4 a c\right ) \sqrt {b d+2 c d x} \sqrt {a+b x+c x^2}}{84 c^3 d^3}+\frac {5 \sqrt {b d+2 c d x} \left (a+b x+c x^2\right )^{3/2}}{42 c^2 d^3}-\frac {\left (a+b x+c x^2\right )^{5/2}}{3 c d (b d+2 c d x)^{3/2}}+\frac {5 \left (b^2-4 a c\right )^{9/4} \sqrt {-\frac {c \left (a+b x+c x^2\right )}{b^2-4 a c}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt {b d+2 c d x}}{\sqrt [4]{b^2-4 a c} \sqrt {d}}\right )\right |-1\right )}{84 c^4 d^{5/2} \sqrt {a+b x+c x^2}}\\ \end {align*}
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Mathematica [C] time = 0.06, size = 101, normalized size = 0.46 \[ -\frac {\left (b^2-4 a c\right )^2 \sqrt {a+x (b+c x)} \, _2F_1\left (-\frac {5}{2},-\frac {3}{4};\frac {1}{4};\frac {(b+2 c x)^2}{b^2-4 a c}\right )}{96 c^3 d \sqrt {\frac {c (a+x (b+c x))}{4 a c-b^2}} (d (b+2 c x))^{3/2}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.73, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (c^{2} x^{4} + 2 \, b c x^{3} + 2 \, a b x + {\left (b^{2} + 2 \, a c\right )} x^{2} + a^{2}\right )} \sqrt {2 \, c d x + b d} \sqrt {c x^{2} + b x + a}}{8 \, c^{3} d^{3} x^{3} + 12 \, b c^{2} d^{3} x^{2} + 6 \, b^{2} c d^{3} x + b^{3} d^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (c x^{2} + b x + a\right )}^{\frac {5}{2}}}{{\left (2 \, c d x + b d\right )}^{\frac {5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.09, size = 1000, normalized size = 4.57 \[ \frac {\left (24 c^{6} x^{6}+72 b \,c^{5} x^{5}+152 a \,c^{5} x^{4}+52 b^{2} c^{4} x^{4}+304 a b \,c^{4} x^{3}-16 b^{3} c^{3} x^{3}+72 a^{2} c^{4} x^{2}+192 a \,b^{2} c^{3} x^{2}-30 b^{4} c^{2} x^{2}+72 a^{2} b \,c^{3} x +160 \sqrt {\frac {2 c x +b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {-\frac {2 c x +b}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {\frac {-2 c x -b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {-4 a c +b^{2}}\, a^{2} c^{3} x \EllipticF \left (\frac {\sqrt {\frac {2 c x +b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {2}}{2}, \sqrt {2}\right )+40 a \,b^{3} c^{2} x -80 \sqrt {\frac {2 c x +b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {-\frac {2 c x +b}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {\frac {-2 c x -b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {-4 a c +b^{2}}\, a \,b^{2} c^{2} x \EllipticF \left (\frac {\sqrt {\frac {2 c x +b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {2}}{2}, \sqrt {2}\right )-10 b^{5} c x +10 \sqrt {\frac {2 c x +b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {-\frac {2 c x +b}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {\frac {-2 c x -b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {-4 a c +b^{2}}\, b^{4} c x \EllipticF \left (\frac {\sqrt {\frac {2 c x +b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {2}}{2}, \sqrt {2}\right )-56 a^{3} c^{3}+60 a^{2} b^{2} c^{2}+80 \sqrt {\frac {2 c x +b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {-\frac {2 c x +b}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {\frac {-2 c x -b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {-4 a c +b^{2}}\, a^{2} b \,c^{2} \EllipticF \left (\frac {\sqrt {\frac {2 c x +b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {2}}{2}, \sqrt {2}\right )-10 a \,b^{4} c -40 \sqrt {\frac {2 c x +b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {-\frac {2 c x +b}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {\frac {-2 c x -b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {-4 a c +b^{2}}\, a \,b^{3} c \EllipticF \left (\frac {\sqrt {\frac {2 c x +b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {2}}{2}, \sqrt {2}\right )+5 \sqrt {\frac {2 c x +b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {-\frac {2 c x +b}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {\frac {-2 c x -b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {-4 a c +b^{2}}\, b^{5} \EllipticF \left (\frac {\sqrt {\frac {2 c x +b +\sqrt {-4 a c +b^{2}}}{\sqrt {-4 a c +b^{2}}}}\, \sqrt {2}}{2}, \sqrt {2}\right )\right ) \sqrt {\left (2 c x +b \right ) d}}{168 \sqrt {c \,x^{2}+b x +a}\, \left (2 c x +b \right )^{2} c^{4} d^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (c x^{2} + b x + a\right )}^{\frac {5}{2}}}{{\left (2 \, c d x + b d\right )}^{\frac {5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (c\,x^2+b\,x+a\right )}^{5/2}}{{\left (b\,d+2\,c\,d\,x\right )}^{5/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + b x + c x^{2}\right )^{\frac {5}{2}}}{\left (d \left (b + 2 c x\right )\right )^{\frac {5}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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